# hcooch3 + naoh

HCOOCH3 + NaOHHCOONa + CH3OH

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### Word Equation

Acetic Acid + Sodium Hydroxide = Sodium Formate + Methanol

One mole of

Acetic Acid [HCOOCH3]

and one mole of

Sodium Hydroxide [NaOH]

react vĩ đại form one mole of

Sodium Formate [HCOONa]

and one mole of

Methanol [CH3OH]

### Reaction Expressions

Kc or Q = ( [HCOONa] [CH3OH] ) / ( [HCOOCH3] [NaOH] )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -(Δ[HCOOCH3] / Δt) = -(Δ[NaOH] / Δt) = (Δ[HCOONa] / Δt) = (Δ[CH3OH] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)

## Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
• Ionic charges are not yet supported and will be ignored.
• Replace immutable groups in compounds vĩ đại avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
• Compound states [like (s) (aq) or (g)] are not required.
• You can use parenthesis () or brackets [].

## How To Balance Equations

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## Balance HCOOCH3 + NaOH = HCOONa + CH3OH Using the Algebraic Method

To balance the equation HCOOCH3 + NaOH = HCOONa + CH3OH using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

1. ### Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable vĩ đại represent the unknown coefficients.

a HCOOCH3 + b NaOH = c HCOONa + d CH3OH

2. ### Create a System of Equations

Create an equation for each element (H, C, O, Na) where each term represents the number of atoms of the element in each reactant or product.

H: 4a + 1b = 1c + 4d C: 2a + 0b = 1c + 1d O: 2a + 1b = 2c + 1d Na: 0a + 1b = 1c + 0d

3. ### Solve For All Variables

Use substitution, Gaussian elimination, or a calculator vĩ đại solve for each variable.

• 4a + 1b - 1c - 4d = 0
• 2a - 1c - 1d = 0
• 2a + 1b - 2c - 1d = 0
• 1b - 1c = 0

Use your graphing calculator's rref() function (or an online rref calculator) vĩ đại convert the following matrix into reduced row-echelon-form:

[ 4 1 -1 -4 0] [ 2 0 -1 -1 0] [ 2 1 -2 -1 0] [ 0 1 -1 0 0]

The resulting matrix can be used vĩ đại determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result vĩ đại get the lowest, whole integer values.

• a = 1 (HCOOCH3)
• b = 1 (NaOH)
• c = 1 (HCOONa)
• d = 1 (CH3OH)
4. ### Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

HCOOCH3 + NaOH = HCOONa + CH3OH

Reactants Products H 5 5 ✔️ 2 2 ✔️ 3 3 ✔️ 1 1 ✔️

Since there is an equal number of each element in the reactants and products of HCOOCH3 + NaOH = HCOONa + CH3OH, the equation is balanced.

## Balance HCOOCH3 + NaOH = HCOONa + CH3OH Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the over of a chemical reaction as at the beginning. To be balanced, every element in HCOOCH3 + NaOH = HCOONa + CH3OH must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used vĩ đại balance one element at a time until both sides are equal and the chemical equation is balanced.

### 1. Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)
ReactantsProducts
HCOOCH3NaOHTotalHCOONaCH3OHTotal
H415145✔️
C22112✔️
O213213✔️
Na1111✔️

The number of atoms of each element on both sides of HCOOCH3 + NaOH = HCOONa + CH3OH is equal which means that the equation is already balanced and no additional work is needed.

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