HCOOCH_{3} + NaOH → HCOONa + CH_{3}OH

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### Word Equation

Acetic Acid + Sodium Hydroxide = Sodium Formate + Methanol

One mole of

and one mole of

react vĩ đại form one mole of

and one mole of

### Reaction Expressions

K_{c} or Q = ( [HCOONa] [CH_{3}OH] ) / ( [HCOOCH_{3}] [NaOH] )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -(Δ[HCOOCH_{3}] / Δt) = -(Δ[NaOH] / Δt) = (Δ[HCOONa] / Δt) = (Δ[CH_{3}OH] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)

## Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- Ionic charges are not yet supported and will be ignored.
- Replace immutable groups in compounds vĩ đại avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
- Compound states [like (s) (aq) or (g)] are not required.
- You can use parenthesis () or brackets [].

## How To Balance Equations

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## Balance HCOOCH3 + NaOH = HCOONa + CH3OH Using the Algebraic Method

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To balance the equation HCOOCH3 + NaOH = HCOONa + CH3OH using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

### Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable vĩ đại represent the unknown coefficients.

a HCOOCH

_{3}+ b NaOH = c HCOONa + d CH_{3}OH### Create a System of Equations

Create an equation for each element (H, C, O, Na) where each term represents the number of atoms of the element in each reactant or product.

**H**: 4a + 1b = 1c + 4d**C**: 2a + 0b = 1c + 1d**O**: 2a + 1b = 2c + 1d**Na**: 0a + 1b = 1c + 0d### Solve For All Variables

Use substitution, Gaussian elimination, or a calculator vĩ đại solve for each variable.

- 4a + 1b - 1c - 4d = 0
- 2a - 1c - 1d = 0
- 2a + 1b - 2c - 1d = 0
- 1b - 1c = 0

Use your graphing calculator's rref() function (or an online rref calculator) vĩ đại convert the following matrix into reduced row-echelon-form:

[ 4 1 -1 -4 0] [ 2 0 -1 -1 0] [ 2 1 -2 -1 0] [ 0 1 -1 0 0]

The resulting matrix can be used vĩ đại determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result vĩ đại get the lowest, whole integer values.

- a = 1 (HCOOCH3)
- b = 1 (NaOH)
- c = 1 (HCOONa)
- d = 1 (CH3OH)

### Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

HCOOCH

_{3}+ NaOH = HCOONa + CH_{3}OHReactants Products H 5 5 ✔️ C 2 2 ✔️ O 3 3 ✔️ Na 1 1 ✔️ Since there is an equal number of each element in the reactants and products of HCOOCH3 + NaOH = HCOONa + CH3OH, the equation is balanced.

## Balance HCOOCH3 + NaOH = HCOONa + CH3OH Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the over of a chemical reaction as at the beginning. To be balanced, every element in HCOOCH3 + NaOH = HCOONa + CH3OH must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used vĩ đại balance one element at a time until both sides are equal and the chemical equation is balanced.

### 1. Count the number of each element on the left and right hand sides

Reactants (Left Hand Side) | Products (Right Hand Side) | ||||||
---|---|---|---|---|---|---|---|

Reactants | Products | ||||||

HCOOCH_{3} | NaOH | Total | HCOONa | CH_{3}OH | Total | ||

H | 4 | 1 | 5 | 1 | 4 | 5 | ✔️ |

C | 2 | 2 | 1 | 1 | 2 | ✔️ | |

O | 2 | 1 | 3 | 2 | 1 | 3 | ✔️ |

Na | 1 | 1 | 1 | 1 | ✔️ |

The number of atoms of each element on both sides of HCOOCH3 + NaOH = HCOONa + CH3OH is equal which means that the equation is already balanced and no additional work is needed.

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