hcooch3 + naoh


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Word Equation

Acetic Acid + Sodium Hydroxide = Sodium Formate + Methanol

One mole of

Acetic Acid [HCOOCH3]

and one mole of

Sodium Hydroxide [NaOH]

react vĩ đại form one mole of

Sodium Formate [HCOONa]

and one mole of

Methanol [CH3OH]

Reaction Expressions

Kc or Q = ( [HCOONa] [CH3OH] ) / ( [HCOOCH3] [NaOH] )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

rate = -(Δ[HCOOCH3] / Δt) = -(Δ[NaOH] / Δt) = (Δ[HCOONa] / Δt) = (Δ[CH3OH] / Δt)

(assuming constant volume in a closed system and no accumulation of intermediates or side products)


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Balance HCOOCH3 + NaOH = HCOONa + CH3OH Using the Algebraic Method

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To balance the equation HCOOCH3 + NaOH = HCOONa + CH3OH using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

  1. Label Each Compound With a Variable

    Label each compound (reactant or product) in the equation with a variable vĩ đại represent the unknown coefficients.

    a HCOOCH3 + b NaOH = c HCOONa + d CH3OH

  2. Create a System of Equations

    Create an equation for each element (H, C, O, Na) where each term represents the number of atoms of the element in each reactant or product.

    H: 4a + 1b = 1c + 4d C: 2a + 0b = 1c + 1d O: 2a + 1b = 2c + 1d Na: 0a + 1b = 1c + 0d

  3. Solve For All Variables

    Use substitution, Gaussian elimination, or a calculator vĩ đại solve for each variable.

    • 4a + 1b - 1c - 4d = 0
    • 2a - 1c - 1d = 0
    • 2a + 1b - 2c - 1d = 0
    • 1b - 1c = 0

    Use your graphing calculator's rref() function (or an online rref calculator) vĩ đại convert the following matrix into reduced row-echelon-form:

    [ 4 1 -1 -4 0] [ 2 0 -1 -1 0] [ 2 1 -2 -1 0] [ 0 1 -1 0 0]

    The resulting matrix can be used vĩ đại determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

    Simplify the result vĩ đại get the lowest, whole integer values.

    • a = 1 (HCOOCH3)
    • b = 1 (NaOH)
    • c = 1 (HCOONa)
    • d = 1 (CH3OH)
  4. Substitute Coefficients and Verify Result

    Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.


    Reactants Products

    Since there is an equal number of each element in the reactants and products of HCOOCH3 + NaOH = HCOONa + CH3OH, the equation is balanced.

Balance HCOOCH3 + NaOH = HCOONa + CH3OH Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the over of a chemical reaction as at the beginning. To be balanced, every element in HCOOCH3 + NaOH = HCOONa + CH3OH must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used vĩ đại balance one element at a time until both sides are equal and the chemical equation is balanced.

1. Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)

The number of atoms of each element on both sides of HCOOCH3 + NaOH = HCOONa + CH3OH is equal which means that the equation is already balanced and no additional work is needed.

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